Square Root Of 256 By Repeated Subtraction Method

45 13 32.

Square root of 256 by repeated subtraction method.

In this article we will learn how to find the square root of a number through repeated subtraction. 65 9 56 56 11 45. Find square root of 9 by repeated subtraction method. Let us find the square root of 81 by repeated subtraction method.

5 5 0 as you can see that given number 9 was repeatedly subtracted by successive odd numbers starting from 1 and we get zero in third step. 100 1 99 99 3 96 96 5 91 91 7 84 84 9 75 75 11 64 64 13 51 51 15 36 36 17 19 19 19 0 to find the square root we subtract successive odd numbers from the number till we obtain 0. 9 1 8 step 2. Find the square root of the number 144 using repeated subtraction method.

17 17 0. 32 15 17. Square root of 81 by repeated subtraction. Every square number can be expressed as a sum of successive odd natural numbers starting from 1.

There are several methods for the same. Ex 6 3 3 find the square roots of 100 and 169 by the method of repeated subtraction. Based on the fact mentioned above repetitive subtraction of odd numbers starting from 1 until n becomes 0 needs to be performed. 72 7 65.

The count of odd numbers used in this process will give the square root of the number n. 80 3 77. Let us consider another example to find the square root of 81 by repeated subtraction. 8 3 5 step 3.

Finding the square root of a number by repeatedly subtracting successive odd numbers from the given square number till you get zero is known as repeated subtraction method. View answer for each of the following find the least number that must be added so that the resulting number is a perfect square. Square root by repeated subtraction. Square root of 100.

77 5 72. 81 1 80. We will use this fact to find the square root of a number by repeated subtraction. To find square root we subtract consecutive odd numbers from number till we obtain 0 square root total numbers subtracted let s take an examplesuppose we need to find 81square root of 8181 1 8080 3 7777 5 7272 7 6565 9 5656 11 4545 13 3232 15 1717 17 0since aft.

We know that the sum of the first n odd natural numbers is n 2. Sum of the first n odd natural numbers is equal to n 2.